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a.) Assume that all of the capacitors are parallel plate capacitors. The size of

ID: 1419649 • Letter: A

Question

a.) Assume that all of the capacitors are parallel plate capacitors. The size of the plates in each capacitor varies, but the space between the plates is the same. Which capacitor (or capacitors) will have the strongest electric field between its plates? Explain.

b.) If the 0.75 µF capacitor were removed from the circuit, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

c.) If the 0.75 µF capacitor were removed from the circuit and replaced by a single wire, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

d.) If the 1.5 µF capacitor were removed from the circuit, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

e.) If the 1.5 µF capacitor were removed from the circuit and replaced by a single wire, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

f.) If the 3.5 µF capacitor were removed from the circuit, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

g.) If the 3.5 µF capacitor were removed from the circuit and replaced by a single wire, what would happen to the charge on each of the other capacitors? (for each capacitor, determine if the charge would increase, decrease, or stay the same).

Please show how to do the problem instead of giving the answer. I am trying to learn and I am very confused. Thank you for your help.

1.5pF

Explanation / Answer

a) 8 uF capacitor will have strongest electric field because voltage across it is largest. E=V/d

b) On 1.5 uF capicitor, charge will decreases , on 15 uF, charge will increase; on remaining, charge will be same. This is because in series combination voltage is divided inversally to capacittance value. Smaller capacitance will have larger share of voltage. When 0.75uF is removed, voltage on 15uF increases and voltage on 1.5uF decreases. So does their charge

c) charge on 15uF will decrease to zero as there will be no voltage across it.

Charge on 1.5uF will increase as whole 10V will be across it.

Charge on remaning capacitors will remain same

d) charge on 0.75uF and 15uF will decrease (becomes zero) as they will not be in connection,

charge on remaining will remain same