The two wires shown in the figure carry currents of I = 4.80 A in opposite direc

Question

The two wires shown in the figure carry currents of I = 4.80 A in opposite directions and are separated by a distance of d_0 = 8.88 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer. -4.32 times 10^-5 T Calculate the net magnetic field at point P_1 - that is 8.72 cm to the right of the wire on the right. Calculate the net magnetic field at point P_2 - that is 21.9 cm to the left of the wire on the left.

Explanation / Answer

here,

I = 4.8 A

d0 = 0.0888 m

x = 0.219 m

the net magnitude of magnetic feild at P2 , B = u0 * I/2pi * ( 1/x - 1/ (d0 + x))

B = 1.26 * 10^-6 * 4.8 /( 2 pi ) * ( 1/0.219 - 1/(0.219 + 0.0888))

B = 1.23 * 10^-6 T

the magnitude of magnetic feild at P2 is 1.23 * 10^-6 T

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