The two wires shown in the figure carry currents of I = 4.67 A in opposite direc

Question

The two wires shown in the figure carry currents of I = 4.67 A in opposite directions and are separated by a distance of d0 = 9.73 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer.

Incorrect.

Tries 2/20

Previous Tries

Calculate the net magnetic field at point P1 - that is 9.02 cm to the right of the wire on the right.

Calculate the net magnetic field at point P2 - that is 19.3 cm to the left of the wire on the left.

Incorrect.

Tries 2/20

Previous Tries

Explanation / Answer

you have not attcahed figure
without figure direction can't be shown
I am calculating magnitudes for you

a)
r1=r2 = 9.73/2 cm = 4.865 cm =4.865*10^-2 m
B1 = miuo*I/2*pi*r1
=(1.2566*10^-6)*(4.67) / (2*pi*4.865*10^-2)
= 1.92*10^-5 T
B2 = miuo*I/2*pi*r2
=(1.2566*10^-6)*(4.67) / (2*pi*4.865*10^-2)
= 1.92*10^-5 T

Bnet = B1+B2
= 1.92*10^-5 T + 1.92*10^-5 T
= 3.84*10^-5 T
Answer: 3.84*10^-5 T

b)
r1 = 9.02 cm = 9.02*10^-2 m
r2= r1+d0 = 9.02 + 9.73 cm = 18.75 cm = 0.1875 m

B1 = miuo*I/2*pi*r1
=(1.2566*10^-6)*(4.67) / (2*pi*9.02*10^-2)
= 1.03*10^-5 T

B2 = miuo*I/2*pi*r2
=(1.2566*10^-6)*(4.67) / (2*pi*0.1875)
= 4.98*10^-6 T

B1 and B2 are in opposite direction
Bnet = B1-B2
= 1.03*10^-5 T - 4.98*10^-6 T
= 5.32*10^-6 T
Answer: 5.32*10^-6 T

C)
r1 = 19.3+9.73 cm = 29.03 cm = 0.2903 m
r2= 19.3 cm = 0.193 m

B1 = miuo*I/2*pi*r1
=(1.2566*10^-6)*(4.67) / (2*pi*0.2903)
= 3.22*10^-6 T

B2 = miuo*I/2*pi*r2
=(1.2566*10^-6)*(4.67) / (2*pi*0.193)
= 4.84*10^-6 T

B1 and B2 are in opposite direction
Bnet = B1-B2
= 3.22*10^-6 T - 4.84*10^-6 T
= - 1.62*10^-6 T
Answer: - 1.62*10^-6 T

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.