Two divers jump out of their boat and swim straight down to a depth of 10 m. The

Question

Two divers jump out of their boat and swim straight down to a depth of 10 m. The water surface becomes calm again very quickly after the divers jump in. Once the divers reach their final depth they begin to swim in opposite directions at the same rate while periodically stopping to shine a flashlight back at the surface of the water where they had jumped in. After the divers have swum far enough apart they begin to notice a strong reflection from the other diver's flashlight that was not present before. How far apart are divers when this starts to happen? (n_air = 1.0, and n_Water = l.33)

Explanation / Answer

Here, sin(theta) = 1/1.33

                           = 48.753   degrees

=> distance between divers = 2 * 10 * tan(48.753)

                                              =   22.808 m

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