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QUESTION #1

A 12.0 kg stone slides down a snow-covered hill (the figure (Figure 1) ), leaving point A with a speed of 10.0 m/s . There is no friction on the hill between points A and B, but there is friction on the level ground at the bottom of the hill, between B and the wall. After entering the rough horizontal region, the stone travels 100 m and then runs into a very long, light spring with force constant 2.10 N/m . The coefficients of kinetic and static friction between the stone and the horizontal ground are 0.20 and 0.80, respectively.

Part A

What is the speed of the stone when it reaches point B?

v2 =

23.15

  m/s  

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Part B

How far will the stone compress the spring?

x=

Explanation / Answer

A) 1/2 m Vo^2 + mgh = 1/2 m v^2

=> 1/2 (100) + 9.8 (20) = 1/2 v^2

=> v = 22.18 m/s


B) 1/2 K x^2 + uk (mg) (100) = 1/2 m VB^2

=> 1.2 x^2 + 0.2 (12 x 9.8) x 100 = 6 (22.18)^2

=.x = 22.36 m <<<<<

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