A +2.00-C point charge is placed at the 0.0 cm mark of a meter stick and a -2.00
ID: 1423709 • Letter: A
Question
A +2.00-C point charge is placed at the 0.0 cm mark of a meter stick and a -2.00-C point charge is placed at the 100.0 cm mark. What is the electric potential at a point above the positive charge at a distance (r) of 6 m from the center of the dipole, at an angle (theta) of 50°?
Answer is 320V
Please show work of how its done
A +2.00-C point charge is placed at the 0.0 cm mark of a meter stick and a -2.00-C point charge is placed at the 100.0 cm mark. What is the electric potential at a point above the positive charge at a distance (r) of 6 m from the center of the dipole, at an angle (theta) of 50°?
Answer is 320V
Please show work of how its done
Explanation / Answer
Pnet = P1 + P2 = kq1/r1 + kq2/r2
Sin50 = r1/6.0
r1= 6.0sin50 = 4.6 m
r2= sqrt(4.6^2 +1^2) = 4.7
Pnet = (9*10^9)[(-2*10^-6)/(4.6) + (2*10^-6)/(4.7)] = -83.3 V
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