Rochester Gas and Electric\'s Robert Emmett Ginna nuclear power plant operates a
ID: 1425939 • Letter: R
Question
Rochester Gas and Electric's Robert Emmett Ginna nuclear power plant operates at a net electric output of 470 MWe. The overall efficiency of the plant is 32.3%. Approximately 60% of the plant's power comes from fissions in 235U, the remainder from fissions in converted plutonium, mostly 239Pu. If the plant were operated at full power for 1 year, how many kilograms of 235U and 239Pu would be (a) fissioned? (b) consumed? Rochester Gas and Electric's Robert Emmett Ginna nuclear power plant operates at a net electric output of 470 MWe. The overall efficiency of the plant is 32.3%. Approximately 60% of the plant's power comes from fissions in 235U, the remainder from fissions in converted plutonium, mostly 239Pu. If the plant were operated at full power for 1 year, how many kilograms of 235U and 239Pu would be (a) fissioned? (b) consumed? Rochester Gas and Electric's Robert Emmett Ginna nuclear power plant operates at a net electric output of 470 MWe. The overall efficiency of the plant is 32.3%. Approximately 60% of the plant's power comes from fissions in 235U, the remainder from fissions in converted plutonium, mostly 239Pu. If the plant were operated at full power for 1 year, how many kilograms of 235U and 239Pu would be (a) fissioned? (b) consumed?Explanation / Answer
Here, power coming from uranium = 470 * 0.6
= 282 MWe
=> energy per year for uranium = 282 * 3600 * 24 * 365
= 8893152000 MJ
=> kilogram of uranium = 8893152000/7.54 * 107
= 117.94 kg
=> kilogram of plutonium = 5928768000/7.54 * 107
= 78.63 kg
(a) kilograms of 235U fissioned = 117.94 kg
kilograms of 239Pu fissioned = 78.63 kg
(b) kilograms of 235U consumed = 117.94 * 100 /32.3
= 365.14 kg
kilograms of 239Pu consumed = 78.63 * 100 /32.3
= 243.43 kg
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