An egg rolls off a kitchen counter and breaks as it hits the floor. The counter

Question

An egg rolls off a kitchen counter and breaks as it hits the floor. The counter is 1.0 m high, the mass of the egg is about 50 g, and the time interval during the collision is about 0.010 s.

Part A

How large is the impulse that the floor exerts on the egg?

Express your answer to two significant figures and include the appropriate units.

Part B

How large is the force exerted on the egg by the floor when stopping it?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

speed of the egg before touching the ground, v = sqrt(2*g*h)

= sqrt(2*9.8*1)

= 4.427 m/s

A)

the impulse that the floor exerts on the egg = change in momentum of the egg

= m*v

= 50*10^-3*4.427

= 0.221 N.s

B) we know, Impulse = Favg*t

==> Favg = Impulse/t

= 0.221/0.01

= 22.1 N

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