Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A ball is thrown with a speed of 1.00m/s at an angle of 85.0o above the horizont

ID: 1427061 • Letter: A

Question

A ball is thrown with a speed of 1.00m/s at an angle of 85.0o above the horizontal. How far does the ball fly before hitting the ground? Prob(3.2) A ball is thrown with a speed of 1.00m/s at an angle of 85.0o above the horizontal. How high is the ball at its highest point? Prob(3.3) A ball is thrown with a speed of 2.00m/s at an angle of 75.0o above the horizontal. How far does the ball fly before hitting the ground? Prob(3.4) A ball is thrown with a speed of 2.00m/s at an angle of 75.0o above the horizontal. How high is the ball at its highest point? Prob(3.5) A ball is thrown with a speed of 3.00m/s at an angle of 65.0o above the horizontal. How far does the ball fly before hitting the ground? Prob(3.6) A ball is thrown with a speed of 3.00m/s at an angle of 65.0o above the horizontal. How high is the ball at its highest point?

Explanation / Answer

here,

initial speed of the ball , u = 1 m/s

theta = 85 degree

(a)

the horizontal range , R = u^2* sin(2*theta) /g

R = 1^2 * sin(85 * 2) /9.8

R = 0.0177 m

the horizontal distance is 0.0177 m

(b)

the maximum height , hmax = u^2 * sin^2(theta) /2g

hmax = ( 1 * sin(85))^2 /( 2 * 9.8)

hmax = 0.051 m

the maximum height is 0.051 m

(c)

u' = 2 m/s and theta' = 75 degree

the horizontal range , R = u'^2* sin(2*theta') /g

R = 2^2 * sin(75 * 2) /9.8

R = 0.204 m

the horizontal distance is 0.204 m

(d)

the maximum height , hmax = u'^2 * sin^2(theta') /2g

hmax = ( 2 * sin(75))^2 /( 2 * 9.8)

hmax = 0.38 m

the maximum height is 0.38 m

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote