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https usb06ca.theexpertta.com Common/TakeTutorialAssignment.aspx The Expert TAIHuman-like Grading, Automated! (13%) Problem 10: A research-level Van de Graaff generator has a 2.05 m diameter metal sphere with a charge of 4.95 mC on it. 33% Part (a) What is the potential near its surface in MV? 33% Part (b) At what distance in meters from its center is the potential 1.00 MV? A 33% Part (co An oxygen atom with two missing electrons is released from rest near the Van de Graaff generator. What is its kinetic energy in MeV at the distance from part b? Grade Summar Deductions 0% 100% Potential Submissions tan 0 7 8 9 cos0 HOME Sin Attempts remaining 20 MA 4 5 6 cotan asin0 acos0 (2 per attempt) detailed view atan acotano sinh0 1 2 3 cosh00 tanh0 cotanh0 Ivo BACKSPACE DIa CLEAR Degrees O Radians Submit Hint I give up! Hints 020 deduction per hint. Hints remaining 3 Feedback 0% deduction per feedback Reade

Explanation / Answer

Here,

radius , R = diameter/2

R = 2.05/2 = 1.025 m

charge ,q = 4.95 mC

part A)

for the electric potential near the surface

potential near the surface = k * q/R

potential near the surface = 9*10^9 * 4.95 *10^-3/1.025

potential near the surface = 4.346 *10^7 V

potential near the surface = 43.46 MV

the potential near the surface is 43.46 MV

part B)

let the distance is d

V = k * q/d

1 *10^6 = 9*10^9 * 4.95 *10^-3/d

solving for d

d = 44.6 m

the distance from the centre is 44.6 m

part C)

here

kinetic energy of the oxygen molecule = change in potential * charge

kinetic energy of the oxygen molecule = (43.46 MV - 1 MV) * 2 e

kinetic energy of the oxygen molecule = 42.46 * 2 * MeV

kinetic energy of the oxygen molecule = 84.92 MeV

the kinetic energy of the oxygen molecule is 84.92 MeV

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