Problem 21.07 .0 A 10-cm-diameter circular loop of wire is placed in a 1.30-T ma
ID: 1427544 • Letter: P
Question
Problem 21.07 .0
A 10-cm-diameter circular loop of wire is placed in a 1.30-T magnetic field.
Part A When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop? Express your answer to two significant figures and include the appropriate units. B =_________
Part B The plane of the loop is rotated until it makes a 42 angle with the field lines. What is the angle in the equation B = BAcos for this situation? Express your answer using two significant figures. =______ degrees
Part C What is the magnetic flux through the loop at this angle? Express your answer to two significant figures and include the appropriate units. B =___________
Explanation / Answer
(a) Flux= BA =(1.3)(pi*0.05^2) = 10.2 mWb
(b) The angle is from the vertical so it is 90-42= 48 degrees
c) Flux at 48 degree angle= BAcos48 = (1.3)(pi*0.05^2)*cos48 = 6.83 mWb
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