Please provide detailed solution A boy pulls a 11.0-kg box with a 100-N force at

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Explanation / Answer

Here ,

mass of block , m = 11 Kg

Force , F = 100 N

theta = 32 degree C

coefficient of kinetic friction, uk = 0.15

distance,d = 34 m

For the net force acting on the block

Normal force acting is N1

N1 = 11 * 9.8 - 100 * sin(32)

N1 = 54.81 N

For the net work done on the box

net work done on the box = F * cos(theta) * d - u * N1 * d

net work done on the box = 100 * cos(32) * 34 - 0.15 * 54.81 * 34

net work done on the box = 2604 J

the net work done on the box is 2604 J

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