An electron(charge -e) is dropped inside the Parallel plate capacitor that has p

Question

An electron(charge -e) is dropped inside the Parallel plate capacitor that has plate area A and distance between plates d. The electron is placed near the positively charged plate and has initial velocity v directed towards the negatively charged Plate (see Fig. 3). Find voltage V between the plates of the capacitor if electron can just reach the negatively charged plate. b) Electric dipole is placed inside the uniform electric field E. Dipole is oriented along the field. Distance between the charges in the dipole is d and absolute value of the charges is q. Find work we need to do to rotate the dipole by 180degree.

Explanation / Answer

C = epsilon_naught*A/d

E.F = surface charge density/epsilon_naught = Q/A*epsilon_naught = C*Voltage/A*epsilon_naught

Accleration = F/m = q*EF/m = e*C*Voltage/(A*epsilon_naught*m)

Apply V^2 - u^2 = 2*a*s

=> v^2 = 2*d*e*C*Voltage/(A*epsilon_naught*m) = 2*d*e*epsilon_naught*A*Voltage/(A*epsilon_naught*m)*d

=> Voltage = mv^2/2e Answer

m = mass of electron

e = charge on electron

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