A long, straight wire carries a current as shown in the figure below. A charged
ID: 1429863 • Letter: A
Question
A long, straight wire carries a current as shown in the figure below. A charged particle moving parallel to the wire experiences a force of 0.60 N at point P.
Cumulative Problem 8 A long, straight wire carries a current as shown in the figure below. A charged particle moving parallel to the wire experiences a force of 0.60 N at point P. 2d 1) Assuming the same charge and same velocity, what would be the magnitude of the magnetic force on the charge at point S? (Express your answer to two significant figures.)Explanation / Answer
here,
Magnatic force is given as:
F = q*v*B--------------------(1)
Where,
q = is charge
v is velocity
B is magnatic Field
also
magantic field at point due to current carrying wire,
B = uo*I/2*pi*d ---------------(2)
Where,
uo = magnatic permeability
d = distance to point
I = Current
Using eqn 2 in 1 we get,
F = q*v*(uo*I)/(2*pi*d) --------------(3)
For Point P, d = d
F1 = (q*v*uo*I)/(2*pi*d)
For Point S, d = 2d
F2 = (q*v*uo*I)/(2*pi*2d)
F2 = F1/2
F2 = 0.6/2
F2 = 0.3 N
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