Two children hang by their hands from the same tree branch. The branch is straig
ID: 1430585 • Letter: T
Question
Two children hang by their hands from the same tree branch. The branch is straight, and grows out from the tree trunk at an angle of 27.0° above the horizontal. One child, with a mass of 43.0 kg, is hanging 1.10 m along the branch from the tree trunk. The other child, with a mass of 27.0 kg, is hanging 2.60 m from the tree trunk. What is the magnitude of the net torque exerted on the branch by the children? Assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.
According to what I know:
(m1g)(lcos 27)+(m2g)(lsin27)=
725.3444683 Nm.
It is saying that it is the wrong answer but everything I look up a solution, this is the formula I get. I don't understand. I have draw six different freebodies and have gone through this problem no less that 10 times. What is it looking for? Help!!!!!!!
Explanation / Answer
m1 = 43 kg
d1 = 1.10 m
m2 = 27 kg
d2 = 2.60 m
angle = 27.0°
we know that
Net torque = m1 * g * d1 cos(29.3 deg) + m2 * g * d2 cos(29.3 deg)
= 44 x 9.8 x 1.10 x cos(27 deg) + 27 x 9.8 x 2.60 x cos(27 deg)
= 1035.59 N.m
Ans: 1035.59 N.m
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