A uniform electric field of magnitude 338 N/C is directed along the +y-axis. A 5

Question

A uniform electric field of magnitude 338 N/C is directed along the +y-axis. A 5.90 µC charge moves from the origin to the point (x, y) = (-40 cm, -36 cm).
(a) What is the change in the potential energy associated with this charge?

______J

(b) Through what potential difference did the charge move?

_______ V

A uniform electric field of magnitude 338 N/C is directed along the +y-axis. A 5.90 muC charge moves from the origin to the point (x, y) = (-40 cm, -36 cm), What is the change in the potential energy associated with this charge? Your response differs from the correct answer by more than 10%. Double check your calculations. 3 Through what potential difference did the charge move?

Explanation / Answer

The charge moves a distance 36cm (0.36m) along (parallel with) the field
Work done in the field = change in elec.PE = F x d = Eq x d ..
> 5.90* 10^(-6) * 338 * 0.36 J =7.1*10^-4mJ
• The change is a gain as the charge is moved 'against' the field direction.

(b), divide the change in potential energy by the charge and you'll get the potential difference between the two points.

Since potential V = J/C
V = J/C
V = (7.1*10^-4) / (5.9*10^-6) =120.33 V

JullyWum · 5 years ago

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