sapling earning io plates separated by a distance 16.8 mm are charged to a poten
ID: 1430778 • Letter: S
Question
sapling earning io plates separated by a distance 16.8 mm are charged to a potential difference of 7.25 volts. A constant 1 N force pushes a -8.30 mC charge from the positively charged plate to the negatively charged plate. Using the concept of work-energy, calculate the change in kinetic energy AT, potential energy AU, and total energy AE of the charge as it travels from one plate to the other. Assume the initial speed of the electron is 0. 7.25 V Number AT Number A 9.81 N Number AE 16.8 mm Previous Give Up & View Solution Check Answer Next Exit HintExplanation / Answer
constant forc = 9.81N
forc of electric field = -Eq = -(V/d) * q = 7.25/(16.8 * 10^(-3)) * (-8.3 * 10^(-3)) = -3.5818
change in kinetic energy
= total work done on the particle
= (const. force - electric field force) * displvcement
=(9.81 -3.5818) * 16.88 * 10^(-3)
= 0.10513J
Change in potential energy = work done against electric force
= electric field force * displvcement
=3.5818 * 16.88 * 10^(-3)
=0.06046J
total energy change
=work done by the external force
=9.81 * 16.88 * 10^(-3)
=0.1656J
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