Chapter 07, Problem 48 | Two particles are moving along the x axis. Particle 1 h

Question

Chapter 07, Problem 48 | Two particles are moving along the x axis. Particle 1 has a massm, and a velocity v velocity of the center of mass of these two particles is zero. In other words, the center of mass of the particles remains stationary, even though each particle is moving. Find the ratio m/m2 of the masses of the particles m04 +3.2 mVs. Particle 2 has a mass m2 and a velocity v2·-7.7 m/s. The n22 n38 Number Units the tolerance is +/-3% 1% TO TEXT g this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor

Explanation / Answer

First problem:

Since the velocity of centre of mass is zero so total linear momentum is conserved, hence ratio of masses m1/m2 is given by the inverse ratio of velocities = v2/v1 = 2.4

Second Problem:

Here we equate the change in momentum with the impulse exerted by the bat on the ball. Let the required average force be F

so F*1.69*10-3 = .155(37.4 - (-46.1)), so F = 7658 N

Third Problem:

a) 92*.50 = 91.75*vw + .25*16 so vw = .45 m/s

b) 92*.50 = 91.75*vw - .25*16, so vw = .54m/s

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