Chapter 07, Problem 42 GO Your answer is partially correct. Try again. A 5.36-g

Question

Chapter 07, Problem 42 GO Your answer is partially correct. Try again. A 5.36-g bullet is moving horizontally with a velocity of +358 m/s, where the sign +indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the fist block is 1183 g, and its velocity is +0.616 m/s after the bullet passes through it. The mass of the second block is 1613 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision. +358 ms Block 1 Block 2 (a) Belove liiun 0.616s mbbck 2 1613g lkt 5.362 slock1 1183g b) After collision (a) Vlock2Number +.735 Units m/s (b) KEafter/KEefore Number .354 Units No units Click if you would like to Show Work for this question: Open Show Work

Explanation / Answer

(a) As calculated

v=0.735 m/s

Kbefore=0.5*5.36*358^2=343479.52

Kafter=0.5*1183*0.616^2+(0.5*(1613+5.36)*0.735^2)=665.2

ratio=1.93*10^(-3)=0.00193

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