An electron is placed in a uniform electric field of E = 1.55 times 10^4 N/C. De

Question

An electron is placed in a uniform electric field of E = 1.55 times 10^4 N/C. Determine the electric force on the electron. Determine the acceleration of the electron if the electron accelerates for a distance of 1.1 cm, and begins from rest, with what speed does it reach the positive plate? Two objects O_1 and O_2 have charges +1 muw C and -2 muw C, respectively. A third object, O_3 is neutral. What is the net electric flux through surface A_1? What is the net electric flux through surface A_2?

Explanation / Answer

Charge of electron

q=-1.6*10-19C

a)

Force due to electric field

F=|q|E =(1.6*10-19)(1.55*104)

F=2.48*10-15 N

b)

mass of electron m=9.11*10-31kg

acceleration

a=F/m =2.48*10-15/9.11*10-31

a=2.72*1015 m/s2

Speed of the electron

V=sqrt[2*a*d]=sqrt[2*2.72*1015*0.011]

V=5.99*1013 m/s2 =6*1013 m/s2

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