Two forces are applied to a car in an effort to move it, as shown in the followi

Question

Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 401 N and F2 = 372 N. (Assume up and to the right as positive directions.) (a) What is the resultant of these two forces?

magnitude ____ N

direction _____° to the right of the forward direction

2. 1.66/4.98 points| Previous Answers SerCP9 4.P.012 My Notes Ask Your Teacher Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 401 N and F2 = 372 N. (Assume up and to the right as positive directions.) 10° 30° Fi Fo (a) What is the resultant of these two forces? magnitudee direction 9.22 to the right of the forward direction (b) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. m/s2 Submit Answer Save Progress

Explanation / Answer

The addition of vector
F1= 401 at 10o,
F2= 372 N at -30o

X component calculation =
Frx = F1x +F2x = 401cos(10) + 372cos(-30)
                      = 394.91+ 322.16= 717.07 N
Y Component Calculation
Fry = F1y + F2y = 401sin(10) + 372sin(-30)
                       = 69.63-186= -116.37

Magnitude= sqrt( (717.07)2 + (-116.37)2)

                  =707.49 N
Angle = tan-1(-116.37/717.07)

        = -9.22o

b)

f=ma

a=f/m

f=f1+f2=773

acceleration, a=773/3000(where m=3000)

=0.258m/sec2

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