A 10.0-v battery is connected in series with the following a 2.00-mue F capacito

Question

A 10.0-v battery is connected in series with the following a 2.00-mue F capacitor, a 5.00-ohm resistor, an ammeter, and a switch, initially open with capacitor uncharged, and a voltmeter connected in parallel across the capacitor. What is the value for the time constant of the circuit? Answer: what is the current reading 3.00 mue s after the switch is closed? Answer: : what is the current reading 3.00 mue s after the switch is closed? Answer: : what is the current capacitor voltage 3.00 mue s after the switch is closed? Answer:

Explanation / Answer

Part A

t = R*C = 5 * 2x10-6 = 1x10-5 s

Part B

Ic (t) = C * dV/dt = C * -Vo/RC * e-t/RC = -1,48 A

Part C

V(t) = Vo * e-t/RC = 7,41 V

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