A 41.0-cm-diameter circular loop is rotated in a uniform electric field until th

Question

A 41.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to the 5.48 Times 10^5 n m^2 /C. What is the magnitude of the electric field? A particular with charge Q = 4.80 mu C is located at the center of cube of edge L = 0.180 m. In addition, six other identical charged particles having q = -1 mu C are positioned symmetrically around Q as shown in the figure below. Determine the electric flux through one face of the cube.

Explanation / Answer

10) d = 41 cm , r = 20.5 cm

flux phi p = 5.48*10^5 N.m^2/C

flux p = E.A= EA cos(theta)

Fro maximum flux theta = 0 degrees

E = p/A =(5.48*10^5/(3.14*0.205*0.205)

E = 4.153*10^6 N/C

E =4.153 MN/C

11) Q = 4.8 uC, L = 0.18 m, q = -1 uC

Net chrge Qinside = (4.8-6*1) = -1.2 uC

eo =8.85*10^-12 C^2/N.m^2

From Gauss law flux = Qinside/eo

flux through one of cube = (1.2*10^-6)/(6*8.85*10^-12)

flux = 22.6 kN.m^2/C

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