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A geostationary communications satellite orbits the earth directly above the equ

ID: 1433103 • Letter: A

Question

A geostationary communications satellite orbits the earth directly above the equator at an altitude of35600 km .

Part A

Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.

Express your answer to three significant figures with the appropriate units.

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Part B

Would this delay be noticeable in a conversation?

A geostationary communications satellite orbits the earth directly above the equator at an altitude of35600 km .

Part A

Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.

Express your answer to three significant figures with the appropriate units.

t =

SubmitMy AnswersGive Up

Part B

Would this delay be noticeable in a conversation?

Would this delay be noticeable in a conversation? Yes No

Explanation / Answer

The distance between the transmitting and receiving points is 2 Re measured through the Earth.
Then the satellite is a distance (35600 + Re) above the centre point of the Earth

The distance to and from the satellite (D) is the hypotenuse of a right-angles triangle .. right-angled sides (Re) and (35600km + Re)

D² = Re² + (35600km + Re)²

D² = (6371km)² + (35600 + 6371km)² .. .. D = 42451.8 km

Total signal path = 2 x D .. .. 84903.6 km

Time taken = D/vel of light = 84903.6km / 3.0^5 km/s .. .. t = 0.28 s

NO it Would not delay

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