A genetics engineer was attempting to cross a tiger and a cheetah. She predicted

Question

A genetics engineer was attempting to cross a tiger and a cheetah. She predicted a phenotypic outcome of the traits she was observing to be in the following ratio 4 stripes only: 3 spots only: 9 both stripes and spots. When the cross was performed and she counted the individuals she found 50 with stripes only, 41 with spots only, and 85 with both. Perform a Chi Square analysis to determine if the genetic engineer get the predicted outcome. O x-0.52, Accepts null hypothesis O x2 24,74. Accepts null hypothesis 0 X2:0.52, Rejects null hypothesis O x2- 4.74, Rejects null hypothesis Moving to another question will save this response Question 1 of 13 >

Explanation / Answer

4/16 * 176 = expected # of stripes = 44

3/16 * 176 = expected # of spots = 33

9/16 * 176 = expected # stripes/spots = 99

Degrees of Freedom = 3 - 1 = 2 (3 different characteristics - stripes, spots, or both)

Chi-square = S (O-E)2/E

D.F. Value

1 3.841

2 5.991

3 7.815

Since 4.74 is less than 5.991, we fail to reject the null hypothesis put forward by the engineer.

expected ratio Observed # Expected # O-E (O-E)2 (O-E)2/E 4 stripes 50 44 6 36 0.82 3 spots 41 33 8 64 1.94 9 stripes /spots 85 99 -14 194 1.98 16 total 176 total 176 total 0 Sum = 4.74

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