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A genetic experiment involving peas yielded one sample of offspring consisting o

ID: 3324068 • Letter: A

Question

A genetic experiment involving peas yielded one sample of offspring consisting of 421 green peas and 144 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow.

Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Explanation / Answer

Test and CI for One Proportion

Test of p = 0.24 vs p 0.24


Sample    X    N Sample p         95% CI         Z-Value P-Value
1       144 421 0.342043 (0.296727, 0.387358)     4.90    0.000

Using the normal approximation.

HoL p = 0.24

Ha: p not equal to 0.24

p^ =X/n = 144/421

TS = (p^ - p)/sqrt(pq/n) = 4.9

p-value = 0.000

p-value < 0.01

we reject the null

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