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A glob of putty thrown to the right bounces off a 0.700-kg cart initially at res

ID: 1433316 • Letter: A

Question

A glob of putty thrown to the right bounces off a 0.700-kg cart initially at rest on a low-friction track. The collision takes 0.15 s, and the coefficient of restitution is 0.76. The cart has a final velocity of 1.0 m/s to the right, and the glob has a final velocity of 0.834 m/s to the left. Suppose that the positive x direction is to the right. What is the inertia of the glob? What is the x component of the average acceleration of the cart during the collision? What is the x component of the average acceleration of the glob during the collision?

Explanation / Answer

Let m be the inertia of glob

e = 1+0.834/V

e = 0.76

V = initial velocity of glob

V = 2.413 m/sec

conserving momentum

m (2.413) = 0.7x1 -m (0.834)

m = 0.21557 kg

acceleration of cart

a = 1/0.15 = 6.67 m/sec^2

acceleration of glob

a =- 0.834-2.413 /0.15

a = -21.646m/sec^2

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