A magician wishes to create the illusion of a 2.5-m-tall elephant. He plans to d

Question

A magician wishes to create the illusion of a 2.5-m-tall elephant. He plans to do this by forming a virtual image of a 57-cm-tall model elephant with the help of a concave spherical mirror.

(a) If the model must be placed 2.04 meters in front of the mirror, how far from the mirror will the image be formed? (Remember: a positive distance corresponds to an image in front of the mirror whereas a negative distance occurs when the image is behind the mirror.) = _______ cm

(b) What radius of curvature is needed? = _________ cm

Main Menu Courses Homework Sets WeBWorK phys251 ww26 2 WW26: Problem 2 Previous i Prob. Listil-Next ) WW26 Problem2 Password/Email Entered Answer Preview Result 894.7 332.2 894.7 ncorrect Grades 332.2 ncorrect Problems At least one of the answers above is NOT corect Problem 1 Problem 2 Problem 3 Problem 4 (2 pts) A magician wishes to create the illusion of a 2.5-m-tall elephant. He plans to do this by forming a virtual image of a 57-cm-tall model elephant with the help of a concave spherical mirror Display Options ew equations as: images (a) If the model must be placed 2.04 meters in front of the mirror, how far from the mirror will the image be formed? (Remember: a positive distance corresponds to an image in front of the mirror whereas a negative distance occurs when the image is behind the mirror.) cm (b) What radius of curvature is needed? jsMath MathJax Show saved answers? cim Yes No Apply Options Note: You can earn partial credit on this problem Preview Answers S Submit answers ubmit Your score was recorded. You have attempted this problem 8 times You received a score of 0% for this attempt

Explanation / Answer

Given,

actual height = h = 57 cm = 0.57 m

illusive height = h' = 2.5 m

(a)We know from the defination of magnification that,

m = -i/o = h'/h = 2.5/0.57 = 4.39

-i/2.04 = 4.39

i = -4.39 x 2.04 = -8.96 m

Hence, image will be formed at, i = -8.96 m = -9 m(aprox) behind the mirror.

(b) we know from lens equation that,'1/f = 1/i + 1/o

1/f = 1/-8.96 + 1/2.04

f = 2.64 m

R = 2 x f = 2 x 2.64 = 5.28 m

Hence, R = 5.28 m = 528 cm.

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