Why do you need to start recording in Part (A) simultaneously with the DC power

Question

Why do you need to start recording in Part (A) simultaneously with the DC power supply? 2. How much voltage (in terms of the power source voltage V_B) will the capacitor have when it has started at zero volts potential difference, it is connected to the power supply and resistor and one characteristic time has past (i.e. t = tau)? Keep a copy - you will need this during your lab and in your report. How much voltage (in terms of the initial charge on the capacitor) will the capacitor have when it is connected to a resistor and one characteristic time has past (i.e. t = tau)? Keep a copy - you will need this during your lab and in your report.

Explanation / Answer

part A:

during the process of charging , fromDC acclumulation of charge takes places

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Power in terms of voltage and resistance is

P = V^2/R

so Volatge variation eqn is V = Vo (1-e^-t/RC)

after one time consatnt t = Rc

so

V = Vo (1-1/e)

V = 0.632 Vo

V = 0.632 sqrt(P R)

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charge Q = CV

V = 0.632 Vo

V = 0.632 (Q/C)

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