a block 6. GPI EC Review. A block having mass m and charge is connected to an WW
ID: 1438191 • Letter: A
Question
a block
Explanation / Answer
For part C, use the conservation of energy to set up an equation:
Ki + Ui = Kf +Uf
and substitute in corresponding components:
0 + QVi = 0 + (1/2 * k*x^2 + QVf)
so simplify to get
1/2 * k*x^2 +Q*E*x
Now solve for x:
x = (2*Q*E) / k
For part D the answer is particle in equilibrium because there is zero net force on it.
Part E, use conclusion from part D, to solve:
The two forces are the spring and the electric force, and we know that
Fs = -kx and Fe = EQ
Fs + Fe = 0
so Fs = - Fe
substitute in values and solve for x:
-kx = -EQ
and so x = EQ / k
Part G, the equation for tension is T = 2pi / angular frequency
and angular frequency = squareroot of (k/m)
so T = 2pi / squareroot of (k/m)
simplifying you get that
T = 2pi * squareroot of (m/k)
The system is isolated because there are no external forces present.
The only types of potential energy present are electrical and elastic potential energy. (kinetic energy is not even a potential energy not sure why its even an option)
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