Go to the simulation at http://phet.colorado.edu/en/simulation/circuit-construct

Question

Go to the simulation at http://phet.colorado.edu/en/simulation/circuit-construction-kit-dc (Click on "Download" and then Open on a Windows machine) or http://phet.colorado.edu/sims/circuit-construction-kit/circuit-construction-kit-dc_en.jnlp. [If this will not run on your computer, please try another browser or computer. It should work on campus lab computers. It works on all the computers in the Learning Resource Center in Osmond 207.] Create a circuit with a battery, two light bulbs in series, and an Ammeter. (How do you connect the Ammeter to your circuit - in series or parallel?)

(1) Is it possible to determine the charge of the particles you see moving? If so, are they meant to be electrons or positive charges?

a) Positive charges

b) Cannot tell from simulation

c) Electrons

2)What current do you measure in Amps?

(3) The battery's default voltage is 9 V. What must be the resistance of one of the light bulb in Ohms?

(4) Now control-click on one of the light bulbs and halve its resistance (we'll call this bulb A and the other bulb B). What happens to the circuit?

a) The current decreases, the bulbs remain equally bright

b) The current decreases, B becomes brighter than A     

c) The current doesn't change, A becomes brighter than B

d) The current increases, the bulbs remain equally bright

e)The current doesn't change, B becomes brighter than A

f)The current decreases, A becomes brighter than B

g) The current increases, A becomes brighter than B

h)The current increases, B becomes brighter than A

(5) Using the Voltmeter, measure the voltage drop across A. It is  Volts.

Explanation / Answer

1.) yes, They are electeron

as only free charges can move due to influence of potential so electron are moving

2.) as both the resistance is connected in series

So net resistance = R1 + R2

Current = V /(R1+R2) A

3.) 2R = 9 / I

R = 4.5 / I { I is current given in Ammeter }

4.) Current increase and B becomes brighter than A

as net current in the circuit increases as Net resistance decreases and in series connection more the resistance more heat will generate so bulb having greater resistance will glow more brighter

5 .) V = IR

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