Go to the simulation at http://phet.colorado.edu/en/simulation/circuit-construct

Question

Go to the simulation at http://phet.colorado.edu/en/simulation/circuit-construction-kit-ac or http://phet.colorado.edu/sims/circuit-construction- kit/circuit-construction-kit-ac_en.jnlp. On a Windows machine, you will probably need to click "Download" and then "Open". [If this will not run on your computer, please try another browser or computer. It should work on campus lab computers and the computers in the PARC in Osmond 207 You may need to tell your computer to allow Java to run.] Create the circuit shown below There is a resistor, a light bulb, one capacitor, one battery, and two switches. Control-click on the battery and change its voltage to 25 V (its default is 9 V). Control-click on the capacitor and change its C to 0.05 F (a) With the top switch open, close the bottom switch. What happens to the charge on the capacitor & the brightness of the bulb as a function of time? O The charge starts large and decreases to zero over time; the bulb starts bright and dims over time O The charge starts large and decreases to zero over time; the bulb starts dim and brightens, reaching a maximum brightness O The charge starts at zero and increases to a maximum value; the bulb starts dim and brightens, reaching a maximum brightness

Explanation / Answer

a)

the charge starts at zero and increase to maximum value , the bulb starts bright and dims over time.

initially the capacitor is uncharged and hence behaves as shortcircuit . hence the current in the circuit is maximum and bulb is brightest.As the capacitor starts charging , the potential difference across the bulb starts decreasing and it becomes dimmer.

b)

The charge decreases over time while brightness of bulb increases

initially the capacitor is fully charged , and it discharges and lose charge . so the voltage across the capacitor decrease while the Voltage across the bulb increase.

c)

the bulb lights only when the capacitor begins charging or discharging.

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