Problem 1 _____________________________ Problem 2 Figure 1 of 1 0 nC 2.0 nC C. 2

Question

Problem 1

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Problem 2

Figure 1 of 1 0 nC 2.0 nC C. 2.0 nC Part A What is the magnitude of the net electric force on charge B in the figure? (Figure 1) Assume a 2.5 cm and b 1.1 cm. Express your answer to two significant figures and include the appropriate units LLA F. Value Units Submit My Answers Give Up Incorrect, Try Again, 3 attempts remaining Part B What is the direction of the net electric force on charge B in the figure? The force is directed up The force is directed down. Submit My Answers Give Up Correct

Explanation / Answer

Fab = kq1q2/a^2 = 9*10^9*1*10^9*2*10^9/0.025^2

Fab = 2.88*10^-5 N

direction will away from middle charge in + y direction

Fbc = kq2q3/b^2 =  9*10^9*2*10^-9*2*10^-9/0.011^2

Fbc = 29.75*10^-5 N

direction will be toward middle charge in +y direction

Fnet = Fab + Fbc = (2.88 + 29.75)*10^-5

Fnet = 32.63*10^-5 N

Direction = in + y direction or 90 degree from +x-axis

2. F = kq1q2/r^2

F = ma

proton is 2.3 fm from surface, so

r = 6/2 + 2.3 = 5.3 fm

F = 9*10^9*54*1.6*10^-19*1.6*10^-19/(5.3*10^-15)^2

F = 442.91 N

a = F/m

a = 442.91/(1.67*10^-27) = 2.652*10^29 m/sec^2

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