In the figure a nonconducting rod of length L = 8.32 cm has charge - q = -4.41 f

Question

In the figure a nonconducting rod of length L = 8.32 cm has charge -q = -4.41 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magnitude and (c) direction (positive angle relative to the positive direction of the x axis) of the electric field produced at point P, at distance a = 13.9 cm from the rod? What is the electric field magnitude produced at distance a = 84 m by (d) the rod and (e) a particle of charge -q = -4.41 fC that replaces the rod?

I have everything but the number for part d please help.

Explanation / Answer

We all know that,

Electric field due to a charged rod = (kQ)/a(l+a) = (9 x 109)( -4.41 x 10-15) / (0.139)(0.139+0.0832) = -1.285 x 10-3 N/C

I aswered to part d only as you have asked.

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