A block is pushed off a table in the horizontal direction, with an initial veloc

Question

A block is pushed off a table in the horizontal direction, with an initial velocity of u = 8.6-m/s. The table is h = 4.1-m tall. Give the initial velocity of the block in the horizontal direction.

answer : ____________m/s

What is the initial velocity in the vertical direction? ________ m/s

Give the magnitude of the acceleration of the block in the horizontal direction. ________________m/s^2

Give the magnitude of the acceleration in the vertical direction. _________m/s^2

How long does the block take to reach the ground? ___________secs

How far from the table in the horizontal direction does the block hit the ground (i.e. what is R in the diagram)? ____________m

Also,,,,,

The engine of a boat drives it across a river that is 8454-m wide. The velocity of the boat is 2.4-m/s relative to the water, perpendicular to the current (travelling from east to west). The velocity of the river is 3.1-m/s in the north direction. Find the magnitude of the velocity of the boat relative to the shore.

_______________m/s

What is the direction of this velocity, measured anti-clockwise from east. ____________ degrees

PLEASE PHYSICS EXPERTS HELP ME

Explanation / Answer

The initial velocity along horizontal direction is ux=8.6 m/s

The initial velocity in vertical direction is zero. uy=0 m/s

The acceleration along horizontal direction is zero, ax=0 m/s^2

use the kinematic equation of motion y=(uy)t+0.5gt^2, and solve for time t.

h=(0)t+0.5gt^2,

t= (2h/g)^1/2 = { (2*4.1 m) / (9.8 m/s^2) }^1/2=0.9147 s

the horizontal distnace travelled by the block before hitting the ground is,

R=(ux)*t = (8.6 m/s)(0.9147 s)=7.86 m

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