Thin lenses. Object O stands on the central axis of a thin symmetric lens. For t

Question

Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (the image distance/' and the lateral magnification m of the object, including signs. Also, determine whether the image is real or virtual, inverted from object O or noninverted, and on the same side of the lens as object O or on the opposite side. Number units Number units virtual noninverted same

Explanation / Answer

focal length for diverging lens negative.

hence f = - 32 cm

object distance, o = 14 cm

using lens equation,

1/f = 1/o + 1/i

1/(-32) = 1/14 + 1/i

i = - 24.89 cm ...........Ans(a)

b) m = - (i/o) = - (24.89 / 14) = 1.78

c) virtual

d) m is +ve, non inverted.

e) same side.

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