Problem 3: (a) Consider the resistor described in problem 1, carrying a current

Question

Problem 3: (a) Consider the resistor described in problem 1, carrying a current of 1.0 mA. If the voltage drop across the resistor is 6.0 Volts, what is the resistance (in k )? (b) Electrical currents crossing the human body in excess of 0.3A are typically deadly. If electrical current has a direct pathway to the heat, it can interfere with your heart beat. In such a case, it only takes about 1 mA to be deadly. Fortunately, under dry conditions, the hand-to-hand resistance of the human body can be as large as 100,000 : This is primarily due to the resistance of your skin. Unfortunately, if your skin is wet or chapped, your resistance can be as low as 1000 . If you touch a 9 Volt transistor battery, placing one hand on the positive electrode, and the other hand on the negative electrode, what will be the current passing through your body with dry skin? With wet skin?

Explanation / Answer

3
(a)
I =1.0 mA
V = 6.0 v

Using Ohm's Law,
V = i*R
R = V/I = 6.0/1.0 *10^-3 = 6000 ohm
R = 6 kohm

(b)
Resistance in dry condition, = 100,000
V= 9 bvolt
V = I*R
I = V/R
I = 9 / 100000 A
I = 0.00009 A

(c)
Resistance in wet condition, = 1000
V = I*R
I = V/R
I = 9 / 1000 A
I = 0.009 A  
I = 9 mA

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