Jason\'s circuit has a 24- resistor that is connected in series to two 12- resis

Question

Jason's circuit has a 24- resistor that is connected in series to two 12- resistors that are onnected in parallel. JoAnna's circuit has three identical resistors wired in parallel. If the equivalent resistance of Jason's circuit is the same as that of JoAnna's circuit, determine the value of JoAnna's resistors. (A) 90 (B) 48 (C) 30 (D) 24 (E) 12 2. Five resistors are connected as shown in the diagram. The potential difference between points A and B is 25 V. 362 3.5 18 24 51 What is the equivalent resistance between the points A and B? (A) 1.5 (B) 4.8 (C) 7.5 (D) 9.4 (E) 11 3, Five resistors are

Explanation / Answer

1)Option (A)90 Ohm is correct answer.

Because;

The equivalent resistance of Jason's circuit will be:

Since 12 Ohm are in parallel to each other, so

1/Rp = 1/12 + 1/12 =

Rp = 12 x 12 / (12 + 12) = 6 Ohm

R1 = 24 Ohm is is in seris with Rp = 6 Ohm

Req = 6 + 24 = 30 Ohm

Now, Joanna's circuit has three identical resistors each of R Ohm connected in parallel, so

1/Req = 1/R + 1/R + 1/R = 3/R

Req = R/3

but, resistance of Jason and Joanna's circuit are equal, So

R/3 = 30 Ohm

R = 90 Ohm

Hence Option (A) 90 Ohm is correct answer.

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2)Option (C)7.5 is correct answer.

Because:

We see from the circuit that, the resistors in last branch are connected in series, so

R1 = 3.5+ 5.1 = 8.6

Now R1 is in parallel with 1.8 Ohm

R2 = 1.8 x 8.6 / (1.8 + 8.6) = 1.49 Ohm

Now R2 is in series with 3.6 and 2.4 Ohm

Rab = 1.49 + 3.6 + 2.4 = 7.5 Ohm

Hence Option (C)7.5 Ohm is correct answer.

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[PS: pls put the other questions seperately].

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