Can I have help with both questions please. I need the answer for both questions
ID: 144237 • Letter: C
Question
Can I have help with both questions please. I need the answer for both questions please. 1) Consider two blood polymorphisms in addition to the ABO blood group. The dominant Rh allele confers the Rh+(rhesus positive) phenotype, whereas the recessive rh allele confers the Rh-(rhesus negative) phenotype. Two codominant alleles, LM and LN determine the M, N, and MN blood groups. Two men took a paternity case to court, each claiming three children to be his own. The blood groups of the men, children, and the mother of the children were as follows: PersonBlood group Husband AB MN Rh- Wife’s lover A M Rh+ Wife B MN Rh+ Child 1 B MN Rh+ Child 2 B N Rh- Child 3 O M Rh- From this evidence, can the paternity of the children be established (assuming no additional lovers)? List the likely male parent for each child. If paternity cannot be established in one or more cases, again give your reasons. 2) Shown below is a pedigree for a disease in dogs, which causes a rare eye abnormality and is inherited recessively. i) Why are the dogs in generation 3 unaffected? Explain in genetic terms. ii) Suppose dogs 1 and 2 had puppies, what fraction of them would you expect to suffer from the condition?Explanation / Answer
Hi,
The husband blood group is AB MN Rh-
so his genotypes are: iAiB LM LN Rh-
The wife blood group is B MN Rh+
her genotye = iBiB or iBio LMLN Rh+
Wife's lover is - A M Rh+
his genotype is iAiA or iAio LMln Rh+
Child 1: B MN Rh+
This is possible with both parents; 1) husband gives one allele iB and wife give iB or iO - child is B. Both parents can give MN, and both can make the child Rh+, Hene the parent of the child 1 cannot be concluded by this test.
Child 2: B N Rh-
Here both parents have equal contribution to B and N is concenrned. But the Rh- can only possilble when Rh- is given by one of the parent. Husband has Rh-. so child 2 is of husband.
Child 3: O M Rh-
The child has O blood; this is possible when both parents give one iO allele. This is not possible with husband as he has no iO allele. Hence this child 3 is of wife lover.
2). This disease occurs in initial 2 generations to all members. Hence it is caused by a dominant allele, lets say D. The dominance does not mean it has to common, any rare gene can be dominant but occur rarely. now lets say the first parents are Dd and DD. So all the children recieved atleast one copy of D causing the disease. The parents of 1 and 2, might have Dd and Dd, so when they mate, there is 1/4 chance of having a dd combination, that is not disease condition. So they might have not inherited the disease.
If the 1 and 2 mate, then they would give rise to healthy ofsprings.
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