Using the direct measurements of the capacitance values for Ca and Cb, calculate

Question

Using the direct measurements of the capacitance values for Ca and Cb, calculate what the expected equivalent capacitance of these two capacitors should be.

Compare this with the measured value for the capacitors connected in series. Repeat this for the parallel circuit arrangement. Report Cp and Cs.

This is a physics lab postlab question.

The data that I got from lab are:

Ca= 2.38 (DMM measrement)

Cb= 4.37 (DMM measurement)

Ca+Cb (in series)= 1.54 (DMM measurement)

Ca+Cb (in parallel)= 6.66 (DMM measurement)

Explanation / Answer

In series

Ceq = C1 x C2 / C1 + C2

Ceq = (2.38 x 4.37) / (2.38 + 4.37)

Ceq = 1.54 (same as measured)

In parallel

Ceq = C1 + C2 = 2.38 + 4.37

Ceq = 6.75

There is a difference of .09 in measured value and calculated value.

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