4.37 isn\'t right either Two blocks are connected over a massless, frictionless
ID: 1442822 • Letter: 4
Question
4.37 isn't right either
Two blocks are connected over a massless, frictionless pulley as shown in the figure above. The mass of block 2 is 10.5 kg, and the coefficient of kinetic friction between block 2 and the incline is 0.200. The angle ? of the incline is 27.5°. If block 2 is moving up the incline at constant speed, what is the mass of block 1?
Two blocks are connected over a massless, frictionless pulley as shown in the figure below. The mass of block 2 is 10.5 kg, and the coefficient of kinetic friction between block 2 and the incline is 0.200. The angle of the incline is 27.5°. If block 2 is moving up the incline at constant speed, what is the mass of block 1? Number 2.99 kg Incorrect You may have switched the direction of the friction force. Block 2 is moving up the incline. Friction always acts in the direction opposite the motion. FrictionExplanation / Answer
The net force acting on the system is zero for constant velocity.
weight force acting on m1
F = m1g
weight of m2 acting parallel to the plane
F = m2gsin
friction force of plane on m2 acts down slope as motion is upslope
Ff = Fn
Ff = m2gcos
m1g - m2g(sin + cos) = 0
m1g = m2g(sin + cos)
m1 = m2(sin + cos)
m1 = 10.5(sin27.5 + 0.200cos27.5)
m1 = 4.87 kg
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