+drawing time object Insert Font Paragraph 14 8 16 Ca 20 40 Cl 17 35 K 19 40 Que
ID: 144316 • Letter: #
Question
+drawing time object Insert Font Paragraph 14 8 16 Ca 20 40 Cl 17 35 K 19 40 Question 1 Using the information above, determine the molarity of a glucose solution where 180g of glucose (C6H1206) is dissolved in 1 liter of water. In addition to calculating the molarity, how many glucose molecules would be present per liter in the final solution? Question 2 You are asked to prepare 2 liters of a 1 M solution of calcium chloride (Cac12). Using the information above, how many grams of calcium chloride would you need to dissolve in the 2 liters of water? Question 3 This question asks you to submit an image as your answer; you can create the image electronically or by hand and submit your image file as your answer. If you draw the answer by hand, you can use a digital camera, scanner or cell phone camera to capture the image for upload Ilustrate a 4C long carbon skeleton with the following functional groups attached. Include H atoms to fill the Catoms where necessary. 100% (+) 8:36Explanation / Answer
Question 2
As per the information given, Molecular mass or Ca = 40 and Cl = 35.
The molecular weight of CaCl2 = 40 + 2(35) = 110
1 Molar solution is a solution in which 1 mole of compound is dissolved in 1 liter of solution.
One gram molecular weight of CaCl2 = 110g
When 110 g of CaCl2 dissolved in 1 liter of water will give 1 M solution of CaCl2.
Therefore, to prepare 2 liters of 1 M solution of CaCl2, the amount of CaCl2 will be required to dissolve in 2 liters of water is = 2 x 110 = 220g
So 220g of CaCl2 need to dissolve in the 2 liters of water.
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