An insect 5.50 mm tall is placed 20.0 cm to the left of a thin planoconvex lens.

Question

An insect 5.50 mm tall is placed 20.0 cm to the left of a thin planoconvex lens. The left surface of this lens is flat, the right surface has a radius of curvature of magnitude 12.2 cm , and the index of refraction of the lens material is 1.70.

Part A

Calculate the location of the image this lens forms of the insect.

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Significant Figures Feedback: Your answer 135 cm was either rounded differently or used a different number of significant figures than required for this part. If you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting your answer.

Part B

Calculate the size of the image.

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Significant Figures Feedback: Your answer 37.1 mm was either rounded differently or used a different number of significant figures than required for this part. If you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting your answer.

Part C

Is the image real or virtual? erect or inverted?

The image is real and inverted .

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Part D

Repeat part A if the lens is reversed.

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Part E

Repeat part B if the lens is reversed.

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Part F

Repeat part C if the lens is reversed.

The image is Please Choosereal and erect real and inverted virtual and erect virtual and inverted  .

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Explanation / Answer

It will be same. Both halves of a convex lens have similar effect. That's why their power value is assumed as half of the lens

Part d

s' = 135 cm

Lensmakers formula is used:

1/o+ 1 / i=(n 1)/R

Part e

|y| =37.1

part f

Image is real inverted

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