The angle of deviation through a triangular prism is defined as the angle betwee
ID: 1445024 • Letter: T
Question
The angle of deviation through a triangular prism is defined as the angle between the incident ray and the emerging ray (angle ?). For an isosceles triangular prism, the angle of the prism is A = 30.0° and the angle of deviation has its minimum value, which is ?min = 20.0°. What is the index of refraction n of the material of the prism?
Please show all work. Thanks!
The angle of deviation through a triangular prism is defined as the angle between the incident ray and the emerging ray (angle ). For an isosceles triangular prism, the angle of the prism is A-30.0% and the angle of deviation has its minimum value, which is Omn-20.0% What is the index of refraction n of the material of the prism? Number 11 = InExplanation / Answer
For a prism
n = sin([A+D]/2)/sin(A/2)
where n is the refractive index of the prism
A = Internal angle of prism
D = Angle of minimum deviation
so n = sin([30+20]/2)/sin(30/2) = sin25/sin15 = 1.632
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