What is the x component of the impulse from 2 on 1? If the y component of the im

Question

What is the x component of the impulse from 2 on 1?

If the y component of the impulse from 1 on 2 is 2034 N s, what is the y component of the average force from 2 on 1?

If the y component of the impulse from 1 on 2 is 2034 N s, what is the y component of the change in momentum for particle 2?

Remember that the mass of particle 1 is 4.1 kg and that the mass of particle 2 is 4.92 kg. If both particles were at rest at the initial time, which particle will have the larger speed at the end of the time interval?

Explanation / Answer

Impulse = J = F.dt

J21 = integral Fa*t^2i + Fb*t^3j from 3.9 to 5.9

J21 = Fa*t^3/3i + Fb*t^4/4j from 3.9 to 5.9

J21 = Fa/3 * [ 5.9^3 - 3.9^3]i + Fb/4 [ 5.9^4 - 3.9^4]

J21 = 774.118i - 2034.3134j

part a )

Jx = 774.118

part b )

F = J/dt = 2034/(5.9-3.9) = 1017 N

part c )

J = cahne in momentum

J = 2034 N

part d )

lighter one have more speed

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