A 0.71-m aluminum bar is held with its length parallel to the east-west directio

Question

A 0.71-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar hits the river below, its speed is 23 m/s, and the emf induced across its length is 7.1 x 10-4 V. Assuming the horizontal component of the Earth's magnetic field at the location of the bar points directly north, (a) determine the magnitude of the horizontal component of the Earth's magnetic field, and (b) state whether the east end or the west end of the bar is positive.

Explanation / Answer

A. Emf = B*v*L

Bh = Emf/vL

Bh = 7.1*10^-4/(23*0.71) = 4.34*10^-5 T

B.

E = vxB

v is down and B is in north direction and so E will be in East direction by vector product.

Let me know if you have any doubt.

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