This question is originally two parts, I got the first part, which was: At what

Question

This question is originally two parts, I got the first part, which was: At what temperature is the rms speed of a molecule of argon gas equal to 2500 m/s? The mass of a argon molecule is 6.680×10-26 kg.

I did (25002 x .04023)/(3 x 8.314)= 10080.9k and then converted the answer to 17685.9 degrees F.

However, I can't get the answer to this question: If you wished to reduce the rms speed of the molecules in argon gas to 1250 m/s, what temperature would be required?

I tried using the same equation but replacing 25002 with 12502 but m homework is saying it is wrong. Please let me know what I'm doing wrong with this second question.

Explanation / Answer

Vrms = sqrt(3kT/m)

1250 = sqrt(3*1.38x10^-23 * T/6.680 x 10^-26)

T = (1250)^2 * 6.68 x 10^-26 / 3 * 1.38*10^-23

T = 2521.135 K

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