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Two resistors. R1=8 ohm and R2=6 ohm, are connected in series. You measured the

ID: 1445688 • Letter: T

Question

Two resistors. R1=8 ohm and R2=6 ohm, are connected in series. You measured the current through R1 is I1 = 1.01A, what is the current (in unit of A) through R2? For the circuit shown below R1 = 10 ohm. R2 = 15 ohm. R3=20 ohm. if the voltage Vis doubled, how will the current through resistor R1 change? Two resistors. R1=9 ohm and R2=23 ohm, are connected in series. You measured the current through R1 is I1=1.26A, what is the voltage across R2? Two resistors. R1=31 ohm and R2=14 ohm, are connected in parallel. You measured the current through R1 is I1=0.98A, what is the current 12 (in unit of A) through R2?

Explanation / Answer

3)

The current through resistors conected in series is the same.
So the current through the R2 is equal to the i1 ====> i2 = i1 = 1.01 A

1.01 A

4)

The current will increase, but not doubled

5)

V2 = i2 R2 = 1.26 * 23 = 29 V

6)

V = I1 R1 = (0.98) * (31) = 30.38 V

I2 = V/R2 = (30.38)/(14) = 2.17 A

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