Two resistors, of R1 = 3.63 ? and R2 = 6.93 ?, are connected in series to a batt

Question

Two resistors, of R1 = 3.63 ? and R2 = 6.93 ?, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I1 through the first resistor and the potential difference ?V2 between the ends of the second resistor. Two resistors, of R1 = 3.63 ? and R2 = 6.93 ?, are connected in series to a battery with an EMF of 24.0 V and negligible internal resistance. Find the current I1 through the first resistor and the potential difference ?V2 between the ends of the second resistor.

Explanation / Answer

i = 24 / (R1 + R2)

i = 24 / (3.63+6.93)

i = 2.2727 A

as , i1 = i2 = i

I1 = 2.273 A

V2 = 2.2727*6.93 = 15.749 V

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