PLEASE SHOW ALL WORK! A particle of charge +4e is initially at rest at coordinat

Question

PLEASE SHOW ALL WORK! A particle of charge +4e is initially at rest at coordinate z = 20 nm on the dipole axis through an electric dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle ? that locates the particle. What is the magnitude of the dipole moment?

In Fig. (a), a particle of charge +4e is initially at rest at coordinate z 20 nm on the dipole axis through an electric dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle that locates the particle, what is the magnitude of the dipole moment? 2.78e-37x Cm te 9

Explanation / Answer

We can calculate the electric field due to the electron at the dipole location.
E = kq/r^2 = 9E9*1.6022E-19/20E-9^2 = 3600000 V/m
Then (see ref.) the energy change deltaU = 4E-30J = 2Ep
==> dipole moment p = 4E-30/(2E) = 8.88 x 10-26 C-m

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